Planet a has mass 3m and radius r, while planet b has mass 4m and radius 2r. they are separated by center-to-center distance 8r. a rock is released halfway between the planets’ centers at point o. it is released from rest. ignore any motion of the planets

. - calculate the magnitude of the rock’s acceleration, in meters per second squared, for m = 7.3×1023 kg and r = 5.8×106 m.

The magnitude of the rock's acceleration half-way between two planets is 1.086 m/s².

The given parameters;

The gravitational force half-way (4R) between the two planets is calculated from Newton's universal gravitational law as follows;

The magnitude of the rock's acceleration is calculated from Newton's second law of motion as follows;

F = ma

Thus, the magnitude of the rock's acceleration is 1.086 m/s².

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The acceleration of rock is .

Given data:

The mass of planet A is, 3M.

The radius of planet A is, R.

The mass of planet B is, 4M.

The radius of planet B is, 2R.

The value of M is, .

The value of R is, .

The gravitational force at halfway (4R) between the two planets is,

Here, G is the universal gravitational constant. Solving as,

Now, the acceleration of rock is calculated as,

Thus, the acceleration of rock is .

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c, 1a hope this

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge