Acircular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 n. the maximum depth in a lake to which the submarine can go without damaging the window is closest to? a. 680mb. 750mc. 1200md. 1327m

Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = N

         g = 9.8 m/s

         radius =

                    = = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F =

or,      h =        

       h =

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

newton's first law of motion