During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (pyrex) beaker of cold coffee. initially, the temperature is 16.2 °c, and the beaker is filled to the brim. a short time later when the student returns, the temperature has risen to 93.5 °c. the coefficient of volume expansion of coffee is the same as that of water. how much coffee (in cubic meters) has spilled out of the beaker?

0.00000938422m^3

Explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container

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