Amass of m1= 3.50 kg is moving toward the right with a velocity of v1= 7.70 m/sec when it collides with a second mass ofm2= 5.50 kg. after the collision the second mass bounces off to the right of the original path of motion of the first ball at anangle ofêb= 27.65owith a speed of v4= 5.16 m/sec.
a. what will be the magnitude of the final velocity v3of the first mass after the collision?
b. what will be the direction of motion êa of the first ball after the collision?
c. how much energy was lost or gained in this collision?
d. was this collision elastic or inelastic? explain

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

resonant frequency

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures

there are no atoms