Abowling ball of mass 5.8 kg moves in a straight line at 4.34 m/s how fast must a ping-pong ball of mass 2.214 g move in a straight line so that the two balls have the same momentum?
answer in units of m/s.

The velocity of the ping-pong ball is, v = 11369.47 m/s

Explanation:

The given data,

The mass of the bowling ball, M = 5.8 kg

The velocity of the ball, V = 4.34 m/s

The mass of the ping-pong ball, m = 2.214 g

                                                          = 0.002214 kg

The velocity of the ping-pong ball, v = ?

The momentum of the bowling ball,

                                             MV = 5.8 x 4.34

                                                    = 25.172 kg m/s

Since the momentum of the balls are equal

                                          MV = mv

                                            v = MV/m

Substituting,

                                             v = 25.172 / 0.002214

                                               = 11369.47 m/s

Hence, the velocity of the ping-pong ball is, v = 11369.47 m/s

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia