2. a car is proceeding at a speed of 14.0 m/s when it collidds with a stationary car in front of it.
during the collision, the first car moves a distance of 3.000 m as it comes tot a stop. the driver
is wearing her seat belt, so she remains in her seat during the collision. if the driver's mass is
52.0 kg, how much force does the belt exert on her during the collision? neglect any friction
between the driver and the seat.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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