Physics, 04.12.2019 04:31 jenesis8

Water flows through a water hose at a rate of q1 = 620 cm3/s, the diameter of the hose is d1 = 2.27 cm. a nozzle is attached to the water hose. the water leaves the nozzle at a velocity of v2 = 12.8 m/s.

a. enter an expression for the cross-sectional area of the hose, a1, in terms of its diameter, d1. sig. gif? tid=6c65-32-87-4c-b016-17686

b. calculate the numerical value of a1, in square centimeters.

c. sig. gif? tid=6c65-32-87-4c-b016-17686enter an expression for the speed of the water in the hose, v1, in terms of the volume flow rate q1 and cross-sectional area a1. sig. gif? tid=6c65-32-87-4c-b016-17686

d. calculate the speed of the water in the hose, v1 in meters per second

e. sig. gif? tid=6c65-32-87-4c-b016-17686enter an expression for the cross-sectional area of the nozzle, a2, in terms of v1, v2 and a1. sig. gif? tid=6c65-32-87-4c-b016-17686

f. calculate the cross-sectional area of the nozzle, a2 in square centimeters.

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Water flows through a water hose at a rate of q1 = 620 cm3/s, the diameter of the hose is d1 = 2.27...

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