Aman is marooned at rest on level frictionless ice. in desperation, he hurls his shoe to the right at 15 m/s. if the man weighs 720 n and the shoe weighs 4.0 n, the man moves to the left at ) 0b) 2.1 x 102 m/s. c) 8.3 x 102 m/s. d) 15 m/s. e) 2.7 x 10-3 m/s 19.

A 0.083 m/s approx 0

Explanation:

mass of the man is 720 N, the mass of the shoe is 4 N, and the man and the shoe were initially at rest. After throwing the shoe, the shoe had a velocity of 15 m/s. Using conservation of momentum:

since the man and the shoe were initially at rest, their initial momentum is zero

0 = M1V1 + M2V2 where M1 is the mass of the shoe ( 4 / 9.81), V1 is the velocity of the shoe 15m/s, M2 is mass of the man ( 720 / 9.81), V2 is the velocity of the man

MAKE V2 subject of the formula

- M1V1 = M2V2

- M1V1 / M2

substitute the values into the equation

- ((4/9.8) × 15) /( 720 / 9.81) = V2

V2 = - 0.0833 m/s approx 0  

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

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