Ahollow ball with a diameter of 3.72 cm has an average density of 0.0841 g/cm3. what force must be applied to hold it stationary while it is completely submerged under water? (enter the magnitude in n, and select the direction from the options given.)

0.2158 N.

Explanation:

Given , The ball has diameter (d)=3.72 cm = 0.0372 m

radius(r) = d/2 = 1.86 cm = 0.0186 m

Average density= 0.0841 g/cm^3 = 84.1 kg/m^3

There are two forces acting on the ball.. i.e. The buoyancy force and weight of the ball.

The force required to completely submerged under water= Buoyancy force - Weight of ball

buoyancy force = volume×density of water×g

[ density of water = 1000 kg/m3]

=0.238 N

mass of ball = average density×Volume

=84.1×4.18×(0.018)^3

=0.0022262 kg

Weight of ball = mg = 0.00204×9.81 =0.02219 N

Required force = 0.238 - 0.02219 = 0.2158 N.

probably not if net force is zero

answer; equivalent to a one(1) horsepower motor;