A0.026 kg bullet is fired straight up at a falling wooden block that has a mass of 5.0 kg. the bullet has a speed of 750 m/s when it strikes the block. the block originally was dropped from rest from the top of a building and had been falling for a time t when the collision with the bullet occured. as a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. find the time t.

0.198 s

Explanation:

Consider the motion of the block  before collision

= initial velocity of block as it is dropped = 0 m/s

= acceleration = - g

= time of travel

= final velocity of block before collision

Using the kinematics equation

= mass of the bullet = 0.026 kg

= velocity of block just before collision = 750 m/s

= mass of the block = 5 kg

= final velocity of bullet block after collision = gt

Using conservation of momentum

vapour or gas assuming atmospheriv pressure

because if the tool that you are using is not balanced it there would be false mass.