Gan object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. if the density of the water is rhow = 1000 kg/m3and the density of the object is rhoob j=500 kg/m3, find the tension in the rope. take g=10 m/s2and assume the object has a uniform mass density

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water,

Density of the object,

Acceleration due to gravity, g =

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V =              (1)

Also, we know that Bouyant force is given by:

Using eqn (1):

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

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