Acell composed of a platinum indicator electrode and a silver-silver chloride reference electrode in a solution containing both fe 2 + and fe 3 + has a cell potential of 0.693 v. if the silver-silver chloride electrode is replaced with a saturated calomel electrode (sce), what is the new cell potential?

0.639 V

Explanation:

The volatge of the cell containing both Ag/AgCl reference electrode and

electrode = 0.693 V

Thus,

E_{anode}=0.197 V

Note: potential of the silver-silver chloride reference electrode (0.197 V)

⇒E_{Cthode}= 0.693+0.197 = 0.890V

To calculate the voltage of the cell containing both the calomel reference

electrode and electrode as follows

Voltage of the cell =

E_{anode}= calomel electrode= 0.241 V

Voltage of the cell = 0.890-0.241 = 0.639 V

Therefore, the new volatge is = 0.639 V

a=d/t

a="triangle"v/t

explanation:

a = acceleration