Anew gel is being developed to use inside padding and helmets to cushion the body from impacts. the gel is stored in a 4.1 m^3 cylindrical tank with a diameter of 2 m. the tank is pressurized to 1.3 atm of surface pressure to prevent evaporation. a total pressure probe located at the bottom of the tank reads 60 ft of water. what is the specific gravity of the gel contained in the tank?

Explanation:

First, we have to calculate the gel's column height using the cylinder's volume, as follows:

Then, as the pressure given at the bottom of the tank is the sum of the surface pressure and the gel's column pressure, we need to calculate only the gel's column pressure:

ft of water is a unit of pressure, but we need to convert it to atm and then to Pa, in order to calculate our results in the correct units. Therefore, the conversion factor is:

1 ft of water (4°C) = 0.0295 atm

Now, to calculate the specific gravity, we need to find first the gel's density:

The specific gravity of the gel is 3.75.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be