Consider an ideal gas enclosed in a 1.00 l container at an internal pressure of 10.0 atm. calculate the work, w, if the gas expands against a constant external pressure of 1.00 atm to a final volume of 25.0 l. i understood how to do this first paer of the did 1atm * 24l = 24.0jthen did -24*101.325= -2431.8it is the second part of the question i do not calculate the work done if this process is carried out in two steps. 1. first, let the gas expand against a constant external pressure of 5.00 atm to a volume of 5.00 l. 2. from there, let the gas expand to 25.0 l against a constant external pressure of 1.00 atm. the answer is -4040 but how do you get that answer?