Physics, 29.11.2019 01:31 boonkgang6821
Suppose the earth's magnetic field at the equator has magnitude 0.5 t and a northerly direction at all points. how fast must a singly ionized uranium atom (m=238u, q=e) move so as to circle the earth 1.44 km above the equator? give your answer in meters/second.
Answers: 2
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Aboat radioed a distress call to a coast guard station. at the time of the call, a vector a from the station to the boat had a magnitude of 45.0 km and was directed 15.0° east of north. a vector from the station to the point where the boat was later found is = 30.0 km, 15.0° north of east. what are the components of the vector from the point where the distress call was made to point where the boat was found? in other words, what are the components of vector c = b - a?
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Suppose the earth's magnetic field at the equator has magnitude 0.5 t and a northerly direction at a...
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