Objects with masses of 255 kg and a 555 kg are separated by 0.390 m.
(a) find the net gravitational force exerted by these objects on a 32.0-kg object placed midway between them.
(b) at what position (other than infinitely remote ones) can the 32.0-kg object be placed so as to experience a net force of zero?

(a). The net gravitational force is

(b). The position is at 0.232 m.

Explanation:

Given that,

Mass of one object M = 255 kg

Mass of another object M'= 555 kg

Separation = 0.390 m

(a). We need to calculate the net gravitational force

Using formula of force

Put the value into the formula

The net gravitational force is

(b). We need to calculate the position

Force from 555 mass = Force from 255 mass

The position is at 0.232 m.

Hence, (a). The net gravitational force is

(b). The position is at 0.232 m.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6