A700-kg elevator starts from rest and moves upward for 3.70 s with constant acceleration until it reaches its cruising speed, 1.76 m/s. (a) what is the average power of the elevator motor during this period

Explanation:

Given that,

Mass of the elevator, m = 700 kg

Time taken, t = 3.7 s

Initial velocity, u = 0

Final velocity, v = 1.76 m/s

Let a is the acceleration of the elevator. Using the first equation of motion to find it as :

The net force acting on the elevator is :

Let P is the average power of the elevator motor during this period. It is given by :

The average power of the elevator is 11488.4 watts. Hence, this is the required solution.

car a and b are moving in opposite directions

plz mark.me the brainliest i rlly need this kind of yours in exchange

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)