A2.0-kg object is attached to a spring (k = 55.6 n/m) that hangs vertically from the ceiling. the object is displaced 0.045 m vertically. when the object is released, the system undergoes simple harmonic motion. what is the magnitude of the maximum acceleration of the object?

Maximum acceleration will be

Explanation:

We have given mass of the object m = 2 kg

Spring constant k = 55.6 N/m

Amplitude is given as A = 0.045 m

We know that maximum acceleration in SHM is given by

Maximum acceleration

We know that

So maximum acceleration =

34.78 m/s^2

Explanation:

mass of object, m = 2 kg

Spring constant, K = 55.6 N/m

Displacement, A = 0.045 m

Angular velocity

ω = 27.8 rad/s

The value of maximum acceleration is given by

a = ω² A

a = 27.8 x 27.8 x 0.045 = 34.78 m/s^2

Thus, the maximum acceleration is 34.78 m/s^2.

if they have a finite resultant

c. newton's third law of motion