Light of wavelength 652 nm in vacuum is incident on a single slit whose width is 1.60 × 10-5 m. the setup is then immersed in water whose index of refraction is 1.33. what is the angle θ that locates the third dark fringe with respect to the central bright fringe?

To solve this problem it is necessary to apply the concepts related to wavelength, refractive index of the materials and the principle of superposition through interference and the two slit experiment for constructive and destructive interference.

For definition the constructive interference is defined as,

Where,

d = Distance between slits

m = Any integer, which is representing the number of repetition of the spectrum (Number of  fringe)

wavelength

Angle

Our values are given as,

641nm

n = 1.33

m=3

Therefore the angle that locates the third dark fringe with respect to the central bright fringe is

The angle θ that locates the third dark fringe with respect to the central bright fringe is 4.616°

a.   mass number from atomic number

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.