Consider a 10 gram sample of a liquid with specific heat 2 j/gk. by the addition of 400 j, the liquid increases its temperature by 10 k and then boils. half of the liquid boils away before all the heat is used up. what is the heat of vaporization of the liquid? a.10 j/gb.20 j/gc.80 j/gd.200 j/ge.40 j/g© 2018.grand canyon university. all rights reserved.

40 J/g is the heat of vaporization of the liquid.

Option D

Explanation:

Given that mass of liquid sample: m = 10 g

And, Specific heat of the liquid: S = 2 J/g K

Also, the increase in the temperature of the liquid,  

Therefore, the total amount of heat energy required is given by:

According to the given data in the question,

Total heat energy supplied, q = 400 J

Rest of heat would be

Now, 200 J vaporizes the mass, half of the liquid from full portion boiled away. So,

Latent heat of vaporization of the liquid is . It can be calculated as below,

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