Aperfectly spherical balloon of air is tethered to the floor of a stagnant body of water by cable ab, and sits just below the surface. the density of water is 1000kg/m3 and the density of air is 1.225kg/m3, given the following: r = 0.53 m a b = 7.95 m what is the tension in cable ab? matlab input: r = 0.53; ab =7.95;

To solve this problem it is necessary to apply the concepts related to Newton's second Law and its definition of density.

By Newton's second law we understand that,

F = ma

Where,

m = mass

a = acceleration (at this case the gravity acceleration)

In the case of density, we know that it is described as the proportion of mass versus volume, that is,

Where,

m = mass

V = Volume

The total tension of the AB cable would be given by the tension exerted upwards by the water and the tension exerted by the weight, therefore,

Mass can be expressed as,

Therefore the tension in cable AB is 6103.94N

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explanation: