Asteel ball, with diameter = 3 mm and density = 7600 kg/m3 is dropped in a liquid with density = 1200 kg/m3 . the average time for the ball to travel a distance of 0.50 m is 10.0 s. a. does the ball rise or fall in the fluid? explain b. determine the fluid viscosity.

Answer

given,

diameter of the steel ball = 3 m = 0.003 m

density of the steel = 7600 kg/m³

density of liquid = 1200 kg/m³

distance travel by the ball = 0.5 m

time = t = 10 s

average velocity =

  v = 0.05 m/s

a) density of water is less than ball so, ball will fall in the fluid.

gravitational force is equal to buoyancy force and the drag force

Density of ball = ρ_s

V is the volume ball

buoyancy force

drag force

μ = 0.63 kg m/s

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.