When an rl circuit is connected to a battery, which is true about its initial and final states?
a. it initially acts like a broken wire and finally acts like ordinary connecting wire.
b. it initially acts like ordinary connecting wire and finally acts like a broken wire.
c. it acts like broken wire throughout the charging.
d. it acts like ordinary connecting wire throughout the charging.

A

Explanation:

In R-L circuit current is given by

where i=current at any time t

R=resistance

L=Inductance

at t=0 approaches to 1

therefore

i=0

when t approaches to ,   approaches to zero

thus

thus we can say that initially circuit act as broken wire with zero current

and it increases exponentially with time and act as ordinary connecting wire

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft