Aneon sign transformer has 500 w ac output with an rms voltage of 16 kv when connected to a normal household outlet. there are 80,000 turns of wire in the secondary coil. when the transformer is running at full power, what is the peak current in the primary coil?

The current in primary coil is 2.08 A.

Explanation:

Given that,

Power = 500 W

Voltage = 16 kV

Number of turns = 80000

We need to calculate the number of current

Using formula of voltage

Put the value into the formula

We need to calculate the current in secondary coil

Using formula of current

We need to calculate the current in primary coil

Put the value into the formula

Hence, The current in primary coil is 2.08 A.