Apotter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. it spins about an axis perpendicular to the disk at its center. a small 1.7 kg lump of very dense clay is dropped onto the wheel at a distance 0.63 m from the axis. what is the moment of inertia of the system about the axis of spin?

Explanation:

Given

Mass of solid uniform disk

radius of disk

mass of lump

distance of lump from axis

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk

Final moment of inertia =Moment of inertia of disk+moment of inertia of lump about axis

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz