Ahammer taps on the end of a 3.4-m-long metal bar at room temperature. a microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. the pulses are separated in time by 8.40 ms .what is the speed of sound in this metal?

S = 2266.67 m/s

Explanation:

Given,

length of the metal = 3.4 m

pulses are separated in time = 8.4 ms

speed of sound in air= 343 m/s

speed of sound in this metal = ?

time taken

t = 9.9 ms

speed of sound in the metal is fast

t = 9.9 - 8.4 = 1.5 ms

time for which sound is in metal is equal to 1.5 ms

speed of sound in metal

S = 2266.67 m/s

Speed of sound in metal is equal to S = 2266.67 m/s

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer