Calculate the angular momentum, in kg. m^2/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.420 kg · m2. kg · m2/s (b) he reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. find the value of his moment of inertia, in kg · m2, if his angular velocity drops to 1.95 rev/s. kg · m2 (c) suppose instead he keeps his arms in and allows friction with the ice to slow him to 3.00 rev/s. what average torque, in n m, was exerted if this takes 23.0 seconds? (indicate the direction with the sign of your answer. assume that the skater's rotation is in the positive direction.) n. m