Asample of an ideal gas initially occupies a volume of 6 l. the pressure of the sample is then doubled while it is cooled to one third its original absolute temperature. after these changes, what volume does the sample occupy?

V₂= 1 L

Explanation:

Given that

Volume occupies V₁= 6 L

Initial pressure = P₁

Initial temperature = T₁

The final pressure =P₂ = 2 P₁

Final volume =V₂

Final temperature = T₁/3

As we know that equation for ideal gas

P V = m R T

P=pressure,  V=volume,   T=temperature

m=mass  ,R=gas constant

Now from mass conservation

6 = 3 x 2 V₂

V₂= 1 L

So the final volume will be 1 L

e) none of the above answers are correct

i think they are all correct

explanation:

they seem good