If an r = 1-kω resistor, a c = 1-μf capacitor, and an l = 0.2-h inductor are connected in series with a v = 150 sin (377t) volts source, what is the maximum current delivered by the source?

Answer

given,

R = 1-kΩ  = 1000 Ω

C = 1-μF

L = 0.2-H

V = V_max sin( ω t)

comparing

V = 150 sin ( 377 t)

ω = 377

Impedance,

Z = 2764.3 Ω

now,

V_{max} = 150 V

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

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