Abaseball is pitched at 30 m/s and hit by a bat. after leaving the bat, the ball has a velocity of 40 m/s. the ball weighs 0.14 kg. the time elapsed during the collision was 0.0020 seconds. what was the force (f) exerted on the baseball? hint: watch your signs of the velocities, the direction changes.

Force exerted on the ball, F = -4900 N

Explanation:

It is given that,

Mass of the ball, m = 0.14 kg

Initial speed of the ball, u = +30 m/s

Final speed of the ball, v = -40 m/s (opposite direction)

Time taken, t = 0.002 s

Let F is the force exerted on the baseball. We know that the force exerted on an object is equal to the product of mass and acceleration. Using second law of motion, the force is given by :

F = ma

F = -4900 N

So, the force exerted on the baseball is -4900 N and it is exerted in opposite direction. Hence, this is the required solution.

an electric circuit

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft