Coherent light of frequency 6.32×1014 hz passes through two thin slits and falls on a screen 87.0 cm away. you observe that the third bright fringe occurs at 3.16 cm on either side of the central bright fringe.

at what distance from the central bright fringe will the third dark fringe occur?

= 4,574 10⁻⁵ m

Explanation:

The interference pattern for a two slit system is given by

    d sin θ = m λ                 constructive interference

    d sin θ= (m + ½) λ          destructive interference

In general and also in this case the screen is far from the slits, so the TT-free can approach the TT

    tan θ = y / L

Let's replace

     d y / L = m λ                   constructive interference

     d y / L = (m + ½) λ          destructive interference

Let's start when there is constructive interference

They give us the frequency of light, let's find the wavelength

    c = λ f

    λ = c / f

    λ = 3 10⁸ / 6.32 10¹⁴

    λ = 4.7468 10⁻⁷ m

Let's take the opportunity to reduce the SI system

    L = 87 cm = 0.87 m

    y = 3.16 cm = 0.0316 m

Now we can find the separation of the slits

   d = m λ L / Y

   d = 3 4.7468 10⁻⁷ 0.87 / 0.0316

   d = 3.92 10⁻⁵ m

We already have all the data, now let's use the destructive interference equation and find

   d / L = (m + ½) λ

    = (m + ½) λ L / d

  = (3 + ½) 4.7468 10⁻⁷ 0.87 / 0.0316

 = 4,574 10⁻⁵ m

the components of a vector are the parts of the vectors that are to each other.

b perpendicular