Let us model the illustrated crusher as a planar mechanism that is subjected to the pushing force p on the lower "l-shaped" handle, i. e. link cde. note that link cde is one solid piece, pinned at d and e. knowing that the orange horizontal member a b has a square peg at a that slides vertically in the slot on the blue frame, that the can is centered under the pin at b and that p = 40 n, θ = 10 o , ϕ = 10 o , a = 75 mm, b = 235 mm, c = 80 mm, and d = 15 mm, determine the force magnitude f in n exerted on the can from the mechanism.

Did the proton move into a region of higher potential or lower potential? did the proton move into a region of higher potential or lower potential? because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential.because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential.because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential.request answerpart bwhat was the potential difference that stopped the proton? express your answer with the appropriate units.î”v î” v = nothingnothingrequest answerpart cwhat was the initial kinetic energy of the proton, in electron volts? express your answer in electron volts.ki k i = nothing ev request answerprovide feedback

Idon’t quite understand this problem

This is the substance(s) formed in a chemical reaction.