(33%) problem 3: two cars collide at an icy intersection and stick together afterward. the first car has a mass of 1100 kg and is approaching at 8.5 m/s due south. the second car has a mass of 650 kg and is approaching at 17.5 m/s due west.

The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

Explanation:

Given that,

Mass of first car = 1100 kg

Velocity of first car = 8.5 m/s

Mass of second car = 650 kg

Velocity of second car = 17.5 m/s

Suppose we need to find the final velocity of the cars and direction of the cars.

We need to calculate the velocity of the car in west direction

Using conservation of momentum in west direction

Put the value into the formula

We need to calculate the velocity of the car in south direction

Using conservation of momentum in south direction

Put the value into the formula

We need to calculate the final velocity of the cars

Using formula of velocity

We need to calculate the direction

Using formula of direction

Put the value into the formula

Hence, The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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