Arace car accelerated uniformly from a speed of 40 m/s to a speed of 58 m/s in 6 seconds while traveling around a circular track of radius 528 m. when the magnitude of the car's total acceleration becomes 5 m/s2. what is its speed (in m/s)? group of answer choices

45.95 m/s

Explanation:

When we talk about circular motion, the object's acceleration (which is a vector quantity) has two components: the centripetal acceleration always directed to the center of the circular track and the tangential acceleration which is tangent to the circular path.

Since both vectors are perpendicular to each other, the magnitude of can be calculated by the Pithagorean Theorem:

(1)

Where:

where is the speed and is the radius of the circle

can be calculated knowing the initial speed () and final speed  () of the car and the time  () it takes to accelerate at this constant rate:

Rewritting (1):

(2)

Isolating :

(3)

(4)

Finally:

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.