Aforce is dependent on position and is given by (4.00 n/m)x+(2.0 n/m2)xy. an object begins at the origin. it first moves in a straight line to x = 1.00 m, y = 0.00 m. it then moves in a straight line to x = 1.00 m, y = 1.00 m. how much work is done on the object by the force during the motion described?

Explanation:

Given that:

Relation of force with position, N

Initial position of the object,

second position of the object,  

final position of the object,  

Now, from the schematic we get the displacement as:

Now we calculate :

The force in X direction for initial displacement

The force in Y direction for initial displacement

Now the resultant force in the direction of displacement:

Therefore work:

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