Two large, parallel, conducting plates are 21 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. an electrostatic force of 3.2 10-15 n acts on an electron placed anywhere between the two plates.

(neglect fringing).

(a) find the magnitude of the electric field at the position of the electron.
n/c

(b) what is the potential difference between the plates?
v

Explanation:

It is given that,

Distance between two conducting plates, d = 21 cm = 0.21 m

Electrostatic force acting on the electron placed anywhere between the two plates,

(a) Let E is the electric field at the position of the electron. The electric force acting on a charged particle per unit charge is called electric field. It is given by :

q is the charge on electron

E = 20000 N

(b) The V is the potential difference between the plates. The relation between the potential difference and the electric field is given by :

V = 4200 volts

Hence, this is the required solution.

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