Adipole is located at the origin, with charges +3 nc and -3 ncseparated by 4 μm. consider a spherical gaussian surfacecentered on the origin of radius 80 μm.

a) what is the electric flux through the gaussiansurface?
b) now suppose you have a gaussian sphere of radius1 μm centered on the positive charge. what is the fluxthrough this gaussian surface?

Explanation:

a )  

The Gaussian surface must  have contained both the charges like +3 nC and - 3 nC , total charges being zero . According the Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times the total charge contained inside the closed surface .

Since total charge inside is zero , total flux will be 1 /  ε₀ x 0 = 0

b )

In this case the Gaussian surface is so small that it contains only the charge

+ 3 nC .

So electric flux over the Gaussian surface

= (  1 /  ε₀ ) x 3 x 10⁻⁹

= (1 / 8.85 x 10⁻¹² ) x 3 x 10⁻⁹

= 3 x 10³ / 8.85

= 339 weber.  

=

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)