Aspecimen of aluminum having a rectangular cross section 9.6 mm × 12.9 mm (0.3780 in. × 0.5079 in.) is pulled in tension with 35600 n (8003 lbf) force, producing only elastic deformation. the elastic modulus for aluminum is 69 gpa (or 10 × 106 psi). calculate the resulting strain.

Explanation:

It is given that,

Dimension of specimen of aluminium, 9.6 mm × 12.9 mm

Area of cross section of aluminium specimen,

Tension acting on object, T = 35600 N

The elastic modulus for aluminum is,

The stress acting on material is proportional to the strain. Its formula is given by :

is the stress

Hence, this is the required solution.

this isn't the answer but they're the graphs

33: i think it’s b