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Physics, 15.11.2019 21:31 joe805

The train's machinist was told that there was an obstacle on the tracks and he would stop before reaching it. when
starts braking, machinist looks the speed radar and reads the speed 144 km/h. deceleration is uniform and the train
stopped ahead the obstacle after 60 seconds.
calculate the train's acceleration in those 60 seconds.
at what distance from train was the obstacle?
clues \\ v0 = 144km. h \\ v = 0 \\ t = 60s \\ a = x \\ d = x \\ a)a = \frac{v - va}{t} \\ b)d = v0 \times t + \frac{at ^{2} }{2}

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