What is the net force on this object: f norm = 20n f frict = 14n f app = 22n f grav = 20n?

8N is the net force on the object.

Explanation:

Given that,

=20N is normal force acting upward (+20N)

=14N is frictional force which is opposite to the applied force (-14N)

22N is applied force which is applied on right side (+22N)

=20N is gravitational force acting downward (-20N)

We know that ,

=applied force +frictional force+normal force +gravitational force

22+(-14)+ 20+(-20)

22-14+20-20

Therefore the net force of the object be 8N.

ill do it for 100, also this isnt 80 its 40

f=ma newton's second law 7x8=56n