Abat strikes a 0.145-kg baseball. just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leaves the bat traveling to the left at an angle of 30 ∘ above horizontal with a speed of 65.0 m/s . the ball and bat are in contact for 1.75 ms .

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball,

Time of contact,

(a) It is assumed to find the horizontal component of average force. It is given by :

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

a person with a mass of 106kg has a weight of 1060n