Acannon ball is fired with an initial velocity of 75 m/s at an angle of 58 degree above the ground. what maximum height will it reach and how far it fly horizontally

h = 206.4 m

range = 515.9 m

Explanation:

from the question we are given the following:

initial velocity (u) = 75 m/s

angle  above surface = 58 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

find the maximum height (h) and the horizontal distance

maximum height (h) =

h =  

h = 206.4 m              

the horizontal distance here is the range

range =

range =

range = 515.9 m

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