Coherent light with wavelength 610 nm passes through two very narrow slits, and theinterference pattern is observed on a screen a distance of 3.00{\rm m} from the slits. the first-order bright fringe is adistance of 4.84 {\rm mm} from the center of the central bright fringe. for what wavelength of light will thefirst-order dark fringe be observed at this same point on thescreen? express your answer in micrometers(not in nanometers).

= 1220 nm

= 1.22 μm

Explanation:

given data:

wavelength

distance of screen from slits D = 3 m

1st order bright fringe is 4.84 mm

condition for 1 st bright is

    ---( 1)

and

= 0.0924 degrees

plug theta value in equation 1 we get

condition for 1 st dark fringe

= 2λ    since from eq (1)

= 1220 nm

= 1.22 μm

answer; how far out of place which the object finished relative to the starting location;

the components of a vector are the parts of the vectors that are to each other.

b perpendicular