An old car is traveling down a long, straight, dry road at 25.0 m/s when the driver slams on the brakes, locking the wheels. the car comes to a complete stop after sliding 275 m in a straight line. if the car has a mass of 755 kg, what is the coefficient of kinetic friction between the tires and the road?

Explanation:

It is given that,

Initial speed of the car, u = 25 m/s

Final speed of the car, v = 0 (it stops)

Distance travelled by the car when it slides, d = 275 m

Mass of the car, m = 755 kg

Let a is the acceleration of the car. Using the third equation of motion to find it as :

The car is decelerating.

Let is the coefficient of kinetic friction between the tires and the road. So,

So, the coefficient of kinetic friction between the tires and the road is 0.11. Hence, this is the required solution.

no sign of dia of fuel cell

that would be because of both gravity and friction. so     c