Acar whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog 50m ahead on its path. if the total force applied on the braking system on the car by the driver is 2000n, what would happen?

The driver hits the stationery dog because the applied force is less than required force

Explanation:

Kinetic energy will be given by

where m is the mass of the vehicle and v is the speed/velocity of the vehicle.

Substituting 800 Kg for m and 20 m/s for v we obtain

Frictional force by vehicle pads is given by

where d is the distance moved

Substituting 160000 for KE and 50 m for d we obtain

Therefore, the vehicle hits the dog since the required force is 3200N but the driver applied only 2000 N

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5