Tarzan, in one tree, sights jane in another tree. he grabs the end of a vine with length 11 m that makes an angle of 45∘ with the vertical, steps off his tree limb, and swings down and then up to jane's open arms. when he arrives, his vine makes an angle of 30∘ with the vertical. determine whether he gives her a tender embrace of knocks her off her limb by calculating tarzan's speed just before he reaches jane. you can ignore air resistance.

1.75 m/s

Explanation:

length of the vine (L) = 11 m

initial angle with the vertical = 45 degrees

final angle with the vertical = 30 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

speed (v) =?

to solve this problem we can apply the equation below:

loss in potential energy = gain in kinetic energy

m x g x h = 1/2 x m x v^{2}

v =

before we can apply the above we need to get our height

height = initial vertical height - final vertical height

height = (L - L cosθ2) -  (L - L cosθ1)

height = (11 - 11cos45) - (11 - 11cos30) = 3.2 m

v =

v = 1.75 m/s

increases it

a is the best answer your welcome