Object a attracts object b with a gravitational force of 10 newtons from a given distance. if the distance between the two objects is doubled,
what is the new force of attraction between them?
a
2.5 newtons
b. 5 newtons
c. 20 newtons
od. 100 newtons

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

that the claims meet official rules.

don't misinterpret the claims

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr