Acarnot engine, operating between hot and cold reservoirs whose temperatures are 800.0 and 400.0 k, respectively, performs a certain amount of work w1. the temperature of the cold reservoir is then lowered to 200.0 k (see the drawing), and the work done by the engine is w2. assuming that the input heat qh is the same in both cases, what is the ratio w2/w1?

The ratio between W2 and W1 is

p=1.5

Explanation:

The W2/W1 ratio equals the efficiency ratio, since the heat input is constant.

Initially, the Carnot efficiency is

1 - (Tc/Th)

1 - 400/800 = 0.50

After lowering Tc, the efficiency becomes

1 - (Tc/Th)  

1 - 200/800 = 0.75

So to determine the ratio between W2 and W1

W2/W1 = 0.75/0.50 = 1.5

! 55 !  

write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model.  

you should have at least 5 complete sentences with a main idea and supporting details.  

you must include the following words:  

potential energy

kinetic energy

mechanical energy

conservation of energy

dude, this is hard lol : ))