When a ball is thrown straight up, by how much does the speed decrease each second? neglect air resistance.

10ms⁻¹

Explanation:

Simply we can consider a motion equation

V = U + a*t

since in upward motion velocity decreases ,

amount of velocity decreased = u-v

V=U -gt ( g =10ms⁻² downwards)

u-v =10*1 ms⁻¹

decreased amount of velocity in a second = 10ms⁻¹

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