Bird bones have air pockets in them to reduce their weight–this also gives them an average density significantly less than that of the bones of other animals. suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 43.0 g and its apparent mass when submerged is 3.60 g (the bone is watertight).a. what mass of water is displaced? b. what is the volume of the bone? c. what is its average density?

a)39ml

b)39g

c)1.1g/ml

Explanation:

Hello!

To solve this exercise use the following steps

1. When Archimedes discovered how to determine the irregular volume of an object by weighing it in the air and in an algua, he found that its volume is equal to the ratio between the differences of the masses (heavy in the air and in the water) and the density of the water (= 1g / ml)

2.as the principle of archimedes says, the displaced volume of water is equal to the volume of the bone which means that 39.4ml of water was displaced, taking into account that the density of water is the ratio between mass and volume we can determine the displaced body of water

3. we use the density equation to find the bone density

15.3 cos 65 degrees trig